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题 求整数 t ,使得关于 x 的方程 x^2+(1-t)x-t^2=0 的解都是整数。
整数 t 只能用陆老师的办法:
Table[Fibonacci[n - 1] Fibonacci[n] Cos[n \[Pi]], {n, 1, 28}]
{0, 1, -2, 6, -15, 40, -104, 273, -714, 1870, -4895, 12816, -33552, 87841, -229970,
602070, -1576239, 4126648, -10803704, 28284465, -74049690, 193864606,
-507544127, 1328767776, -3478759200, 9107509825, -23843770274, ......}
如果去掉负号,这样也可以:LinearRecurrence[{2, 2, -1}, {0, 1, 2}, 100]
{0, 1, 2, 6, 15, 40, 104, 273, 714, 1870, 4895, 12816, 33552, 87841, 229970,
602070, 1576239, 4126648, 10803704, 28284465, 74049690, 193864606, 507544127,
1328767776, 3478759200, 9107509825, 23843770274, 62423800998, 163427632719,
427859097160, 1120149658760, 2932589879121, 7677619978602, 20100270056686,
52623190191455, 137769300517680, 360684711361584, 944284833567073, ......... |
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