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本帖最后由 愚工688 于 2022-8-1 05:31 编辑
200亿的连续偶数素数对下界数量的高精度计算:(可以比较180亿偶数的计算式的修正系数,仍然没有变化)
inf( 20000000000 )≈ 34187864.9 , jd ≈0.99952 ,infS(m) = 25640898.64 , k(m)= 1.33333
inf( 20000000002 )≈ 25908142.7 , jd ≈0.99963 ,infS(m) = 25640898.64 , k(m)= 1.01042
inf( 20000000004 )≈ 51281797.3 , jd ≈0.99943 ,infS(m) = 25640898.64 , k(m)= 2
inf( 20000000006 )≈ 30769078.4 , jd ≈0.99942 ,infS(m) = 25640898.65 , k(m)= 1.2
inf( 20000000008 )≈ 25640898.7 , jd ≈0.99929 ,infS(m) = 25640898.65 , k(m)= 1
inf( 20000000010 )≈ 68375729.8 , jd ≈0.99928 ,infS(m) = 25640898.65 , k(m)= 2.66667
inf( 20000000012 )≈ 25815326.5 , jd ≈0.99934 ,infS(m) = 25640898.65 , k(m)= 1.0068
inf( 20000000014 )≈ 26873618.8 , jd ≈0.99942 ,infS(m) = 25640898.66 , k(m)= 1.04808
inf( 20000000016 )≈ 51770195.4 , jd ≈0.99941 ,infS(m) = 25640898.66 , k(m)= 2.01905
inf( 20000000018 )≈ 25641655.3 , jd ≈0.99956 ,infS(m) = 25640898.66 , k(m)= 1.00003
inf( 20000000020 )≈ 52653969.8 , jd ≈0.99924 ,infS(m) = 25640898.66 , k(m)= 2.05351
inf( 20000000022 )≈ 51553129.6 , jd ≈0.99956 ,infS(m) = 25640898.67 , k(m)= 2.01058
time start =12:39:33 ,time end =12:43:58 ,time use =
计算式:
inf( 20000000000 ) = 1/(1+ .1535 )*( 20000000000 /2 -2)*p(m) ≈ 34187864.9
inf( 20000000002 ) = 1/(1+ .1535 )*( 20000000002 /2 -2)*p(m) ≈ 25908142.7
inf( 20000000004 ) = 1/(1+ .1535 )*( 20000000004 /2 -2)*p(m) ≈ 51281797.3
inf( 20000000006 ) = 1/(1+ .1535 )*( 20000000006 /2 -2)*p(m) ≈ 30769078.4
inf( 20000000008 ) = 1/(1+ .1535 )*( 20000000008 /2 -2)*p(m) ≈ 25640898.7
inf( 20000000010 ) = 1/(1+ .1535 )*( 20000000010 /2 -2)*p(m) ≈ 68375729.8
inf( 20000000012 ) = 1/(1+ .1535 )*( 20000000012 /2 -2)*p(m) ≈ 25815326.5
inf( 20000000014 ) = 1/(1+ .1535 )*( 20000000014 /2 -2)*p(m) ≈ 26873618.8
inf( 20000000016 ) = 1/(1+ .1535 )*( 20000000016 /2 -2)*p(m) ≈ 51770195.4
inf( 20000000018 ) = 1/(1+ .1535 )*( 20000000018 /2 -2)*p(m) ≈ 25641655.3
inf( 20000000020 ) = 1/(1+ .1535 )*( 20000000020 /2 -2)*p(m) ≈ 52653969.8
inf( 20000000022 ) = 1/(1+ .1535 )*( 20000000022 /2 -2)*p(m) ≈ 51553129.6
20000000000:13:2
偶数素数对真值:
G(20000000000) = 34204396
G(20000000002) = 25917735
G(20000000004) = 51311042
G(20000000006) = 30786908
G(20000000008) = 25659138
G(20000000010) = 68425196
G(20000000012) = 25832326
G(20000000014) = 26889096
G(20000000016) = 51800888
G(20000000018) = 25653066
G(20000000020) = 52694224
G(20000000022) = 51575932
G(20000000024) = 25668250
count = 13, algorithm = 2, working threads = 2, time use 8.404 sec
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